The Switch Statement

The switch statement is similar to the else-if construct but has more flexibility and a clearer format. Let's create a four function calculator using switch statement:


included files
void main()
{
 float num1=1.0,num2=1.0;
 char operator;
 while(!(num1==0.0 && num2==0.0))
 {
  printf("Type number, operator, number\n");
  scanf("%f %c %f",&num1,&operator,&num2);
  switch(operator)
   {
    case'+':
    printf(" = %f",num1 + num2);
    break;
    case'-':
    printf(" = %f",num1 - num2);
    break;
    case'*':
    printf(" = %f",num1 * num2);
    break;
    case'/':
    printf(" = %f"num1 / num2);
    break;
    default:
     printf("Unknown Operator!");
   } 
 printf("\n\n")
 }
getch();
}


In the above code, the statement 'case' is working as 'if', while 'default' is working as 'else' statement...


If you have any question, you can ask me freely!

Create a Calculator by using if-else statement

Just copy the code...


#include<stdio.h>
#include<conio.h>
void main (void)
{
 char ch;
 float num1,num2;
 clrscr();
 printf("What do you want to do?\n");
 printf("Addition, Subtraction, Multiplication or Division:");
 ch=getche();
 printf("\nEnter first number:");
 scanf("%f",&num1);
 printf("\nEnter second number:");
 scanf("%f",&num2);
 printf("\n\n");


if(ch=='A')   
 printf("%f %c %f = %.2f",num1,+,num2,num1+num2);

if(ch=='S')   

 printf("%f %c %f = %.2f",num1,-,num2,num1-num2);

if(ch=='M')   

 printf("%f %c %f = %.2f",num1,*,num2,num1*num2);

if(ch=='D')   

 printf("%f %c %f = %.2f",num1,/,num2,num1/num2);

getch();  

}


What is this?

• scanf();
• clrscr();